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Normalize -0.0 in number hashes and test range ends
operator== compares numbers exactly since #5459, so equal numbers share one value and convert to the same number_float_t. Update the comment accordingly, map -0.0 to 0.0 before hashing (std::hash need not do that), and test -0.0 and the ends of the integer ranges. Show hash(0.0) in the docs example and note the change in the version history. Signed-off-by: Niels Lohmann <mail@nlohmann.me>
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@@ -37,3 +37,5 @@ whether they are stored as `#!cpp 0`, `#!cpp 0U`, or `#!cpp 0.0`.
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- Added in version 1.0.0.
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- Extended for arbitrary basic_json types in version 3.10.5.
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- Numbers that compare equal hash equally since version 3.13.0; before, `#!cpp 0`, `#!cpp 0U`, and `#!cpp 0.0` had
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different hash values.
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@@ -11,6 +11,7 @@ int main()
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<< "hash(false) = " << std::hash<json> {}(json(false)) << '\n'
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<< "hash(0) = " << std::hash<json> {}(json(0)) << '\n'
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<< "hash(0U) = " << std::hash<json> {}(json(0U)) << '\n'
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<< "hash(0.0) = " << std::hash<json> {}(json(0.0)) << '\n'
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<< "hash(\"\") = " << std::hash<json> {}(json("")) << '\n'
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<< "hash({}) = " << std::hash<json> {}(json::object()) << '\n'
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<< "hash([]) = " << std::hash<json> {}(json::array()) << '\n'
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@@ -2,6 +2,7 @@ hash(null) = 2654435769
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hash(false) = 2654436030
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hash(0) = 2654436221
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hash(0U) = 2654436221
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hash(0.0) = 2654436221
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hash("") = 11160318156688833227
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hash({}) = 2654435832
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hash([]) = 2654435899
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