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fix: leave the character that terminates a number in the input

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Read the character following a number without consuming it, instead of
consuming it and putting it back. input_stream_adapter now peeks with
sgetc() and only steps over the character when the next one is requested
or when the adapter is destroyed, so releasing it cannot fail - no
putback position is required from the streambuf.

Suggested by gregmarr in #5344.

Signed-off-by: Niels Lohmann <mail@nlohmann.me>
This commit is contained in:
Niels Lohmann
2026-08-04 14:39:05 +02:00
parent e4aaf46d38
commit c021a09b08
6 changed files with 184 additions and 119 deletions
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include/nlohmann/detail/input/parser.hpp
+5 -5
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@@ -102,8 +102,8 @@ class parser
if (!strict)
{
// the caller keeps using the input: position it right after
// the value by giving back the character that terminated it
m_lexer.restore_pending_unget();
// the value by leaving the character that terminated it
m_lexer.release_lookahead();
}
// in strict mode, input must be completely read
else if (get_token() != token_type::end_of_input)
@@ -136,7 +136,7 @@ class parser
if (!strict)
{
// see above
m_lexer.restore_pending_unget();
m_lexer.release_lookahead();
}
// in strict mode, input must be completely read
else if (get_token() != token_type::end_of_input)
@@ -179,8 +179,8 @@ class parser
if (result && !strict)
{
// the caller keeps using the input: position it right after the
// value by giving back the character that terminated it
m_lexer.restore_pending_unget();
// value by leaving the character that terminated it
m_lexer.release_lookahead();
}
// strict mode: next byte must be EOF
else if (result && strict && (get_token() != token_type::end_of_input))