Convert long doubles under a multi-byte decimal point completely

The strtold fallback, which is left only for long double formats that
are not binary64 (x87, binary128), substituted the first byte of the
locale's decimal point for '.'. Under a locale whose decimal point is
longer than one byte, such as fa_IR.UTF-8 or ar_EG.UTF-8 (U+066B),
strtold stopped there and the value was truncated at the decimal point.
A longer decimal point is now put into a copy of the token.

The test "locale with a multi-byte decimal point" now compares the long
double values with those of the "C" locale; with x87 long doubles it
failed before.

Fixes #5660.

Signed-off-by: Niels Lohmann <mail@nlohmann.me>
This commit is contained in:
Niels Lohmann
2026-09-30 20:19:11 +02:00
committed by GitHub
parent 44ec53c77b
commit 9c71689715
4 changed files with 101 additions and 65 deletions
@@ -74,7 +74,8 @@ otherwise, it uses unsigned integer storage.
- The library converts integers and floating-point numbers itself, independent of the locale. Floating-point
numbers are correctly rounded (to nearest, ties to even). Only a `#!c long double` that is not IEEE 754 binary64
(e.g., the 80-bit x87 format) is converted with `#!cpp std::from_chars` where available, or with
[`std::strtold`](https://en.cppreference.com/w/cpp/string/byte/strtof).
[`std::strtold`](https://en.cppreference.com/w/cpp/string/byte/strtof), which gets the decimal point of the
current locale, also one longer than one byte (e.g., in `fa_IR.UTF-8`).
!!! example "Examples"